In May 2025, a research team observed a section of the night sky continuously for several days. One star appears to change its brightness. Here is a plot of its apparent magnitude: with such a behaviour are called Cepheids and their absolute magnitude can

Добавлена: 03.05.2026
Обновлена: 03.05.2026
Предмет: Астрономия
Автор: Кэмп

#Практикум по наблюдательной астрономии
#Астрофизика звезд

Условие:

In May 2025, a research team observed a section of the night sky continuously for several days. One star appears to change its brightness. Here is a plot of its apparent magnitude: \nStars with such a behaviour are called Cepheids and their absolute magnitude $M$ can be calculated by applying the Leavitt Law (Period-Luminosity relation)

M=-2.43 \cdot\left(\log _{10}(T)-1\right)-4.05,

\nwhere

T

is the star's pulsation period in days. The research team finds that the star's average apparent magnitude is 6.5 mag. Determine the star's distance to the Earth in parsecs.

Решение:

Из условия задачи следует, что звезда —Cepheid, модуль абсолютной величины которой вычисляется по закону Левитта:
M = –2.43 · (log10(T) – 1) – 4.05,
где T – период пульсации в днях. С учётом того, что на типичных графиках периода для этих звёзд часто выбирают T = 10 дней (так как log10(...