3. Lazer nurining to'lqin uzunligi λ=630 ~nm bo'lsa, fotonining energiy asini, massasini va impulsinitoping. Yorug'likning tarqalish tezligi c=3 108 ~m / s, Plank doimiysi h=6,625 1034 ~J* c.

Keling, berilgan malumotlar asosida foton energiyasini,...

Foton energiyasi \( E \) quyidagi formula orqali hisoblanadi: \[ E = \frac{h \cdot c}{\lambda} \] Bu yerda: - \( h = 6.625 \times 10^{-34} \, \text{J} \cdot \text{s} \) (Plank doimiysi) - \( c = 3 \times 10^{8} \, \text{m/s} \) (yoruglik tezligi) - \( \lambda = 630 \, \text{nm} = 630 \times 10^{-9} \, \text{m} \) (tolqin uzunligi) Endi formulaga qiymatlarni qoyamiz: \[ E = \frac{(6.625 \times 10^{-34}) \cdot (3 \times 10^{8})}{630 \times 10^{-9}} \] Hisoblaymiz: \[ E = \frac{(6.625 \times 3) \times 10^{-34 + 8 + 9}}{630} \] \[ E = \frac{19.875 \times 10^{-17}}{630} \] \[ E \approx 3.16 \times 10^{-19} \, \text{J} \] Foton massasi \( m \) quyidagi formula orqali hisoblanadi: \[ m = \frac{E}{c^2} \] Endi energiyani va yoruglik tezligini qoyamiz: \[ m = \frac{3.16 \times 10^{-19}}{(3 \times 10^{8})^2} \] Hisoblaymiz: \[ m = \frac{3.16 \times 10^{-19}}{9 \times 10^{16}} \] \[ m \approx 3.51 \times 10^{-36} \, \text{kg} \] Foton impulsini \( p \) quyidagi formula orqali hisoblaymiz: \[ p = \frac{E}{c} \] Endi energiya va yoruglik tezligini qoyamiz: \[ p = \frac{3.16 \times 10^{-19}}{3 \times 10^{8}} \] Hisoblaymiz: \[ p \approx 1.05 \times 10^{-27} \, \text{kg} \cdot \text{m/s} \] 1. Foton energiyasi: \( E \approx 3.16 \times 10^{-19} \, \text{J} \) 2. Foton massasi: \( m \approx 3.51 \times 10^{-36} \, \text{kg} \) 3. Foton impuls: \( p \approx 1.05 \times 10^{-27} \, \text{kg} \cdot \text{m/s} \)