Вариант 4 egin{array}{l} F(X)=-2 x{1}+5 x{2} → max (min ) \ ≤ft{egin{array}{l} -3 x{1}+2 x{2} ≤ 12 \ x{1}+2 x{2}=8 \ x{1}+x{2} ≥ 5 \ x{1}, x{2} ≥ 0 end{array} ight. end{array}
Вариант 4 egin{array}{l} F(X)=-2 x{1}+5 x{2} → max (min ) \ ≤ft{egin{array}{l} -3 x{1}+2 x{2} ≤ 12 \ x{1}+2 x{2}=8 \ x{1}+x{2} ≥ 5 \ x{1}, x{2} ≥ 0 end{array} ight. end{array}